To evaluate the effect of a treatment, a sample of n = 9 is obtained from a population with a mean of μ = 40, and the treatment is administered to the individuals in the sample. After treatment, the sample mean is found to be M = 33. If the sample has a standard deviation of s = 9, do we reject or accept the null hypothesis using a two-tailed test with alpha = .05?

Yes we reject the null hypothesis

Step-by-step explanation:

From the question we are told that

  The sample size is  

   The  population mean is  

    The  sample  mean is  

    The  standard deviation is

    The  level of significance is  

For a two-tailed test

The  null hypothesis is  

The alternative hypothesis is  

Generally the test statistics is mathematically represented as

=>    

=>    

The  p-value for the two-tailed test  is mathematically represented as

From the z-table  

Given that Then we reject the null hypothesis

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.