PLEASE HELP I'm desperate. Algebra. −2x+3y−z=−2
3x+y=4
−2y+2z=4

3x+2y−z=8
2x+2z=−4
x+3y=4

2x−y+2z=−6
−3y+z=−2
2x−3z=4

x+y+z=10
−2x−2y−z=−32
3x−2y+2z=−8

x+3y−z=6
4x−2y+2z=−10
6x+z=−12
Enter your answer, in the form (x, y,z), in the boxes in simplest terms.
If you can please help me with these, How you solved it would help too, but I need the answers ASAP. Thank you so much.

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.