A 2-column table with 10 rows. The first column is labeled x with entries negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4, 5. The second column is labeled f of x with entries 105, 0, negative 15, 0, 9, 0, negative 15, 0, 105, 384. According to the table, which ordered pair is a local minimum of the function, f(x)?

(0, 9)
(4, 105)
(–1, 0)
(2, –15)

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

i think the answer is b

hi im bob : l

step-by-step explanation: