The sum of the squares of two consecutive real numbers is 61. Find the numbers.

1. (5 ; 6)

2. (-5 ; -6)

consecutive numbers => x ; (x + 1)

x² + (x + 1)² = 61

x² + x² + 2x + 1 = 61

2x² + 2x + 1 - 61 = 0

2x² + 2x - 60 = 0 | : 2

x² + x - 30 = 0

x =

x =

x =

x₁ =

x₂ =

Solutions

1. (5 ; 6)

5² + 6² = 25 + 36 = 61

2. (-5 ; -6)

(-5)² + (-6)² = 25 + 36 = 61

idk

step-by-step explanation:

idk

step-by-step explanation:

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