Javier writes an integer on a piece of paper. The absolute value of his number is less than 4. Which is true of the possible values of Javier's number?

3, -2, -1, 0, 1, 2, 3

Step-by-step explanation:

Given the inequality expression |x| < 4 where x is unknown. To her the possible values of x, we must undeterstand that the absolute value of a number returns both positive and negative value.

Hence |x| can either return +x or -x

If x is positive, the inequality expression will be x<4.

If the value of x is negative, then -x<4

From -x<4

Multiply both sides by minus sign will change the sense of the inequality sign.

-(-x) > -4

x>-4

If x is greater than -4, then -4<x.

Combining both inequality will give;

-4 < x and x<4

-4<x<4

Hence the possible values of Javier's number are integers between -4 and 4.

The values are -3, -2, -1, 0, 1, 2, 3.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!