How many pennies could you have if: When you break the pennies into groups of 2, you have
1 penny left over, AND when you break the pennies into
groups of 3, you have 1 penny left over, AND when you
break the pennies into groups of 5, you have 1 penny
left over, AND when you break the pennies into groups
of 7, you have NO pennies left over?

The number of pennies are 91 pennies

Step-by-step explanation:

The given parameters are

When we split the pennies in twos the number left = 1

When the pennies are split in 3s the number left = 1

When the pennies are split in 5s the number left = 1

When the pennies are split in 7 the number left = 0

Therefore, 7 is a factor of the number

Given that when the pennies are split in 5s the number left = 1, the number ends with a 1

We have the products of 7 ending with 1 from Excel as 21 and 91, 161...

We check 91 given 21 is directly divisible by 3 as follows;

91/2 = 45 remainder 1

91/3 = 30 remainder 1

91/5 = 18 remainder 1

91/7 = 13 remainder 0

Therefore, the number of pennies are 91 pennies.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*