A dolphin jumps from the water with an initial velocity of 44 feet per second at an elevation angle of 60°. Which parametric equations model the dolphin’s path through the air? x(t) = sin(60°)t + 44 and y(t) = –16t2 + cos(60°)t + 44 x(t) = cos(60°)t + 44 and y(t) = –16t2 + sin(60°)t + 44 x(t) = 44sin(60°)t and y(t) = –16t2 + 44cos(60°)t x(t) = 44cos(60°)t and y(t) = –16t2 + 44sin(60°)t Please help quickly!

B

Step-by-step explanation:

first write t in terms of x

x = 7t - 3

7t = x+3

t = x/7 + 3/7

plug into y

y = 5t+1

y = 5x/7 + 15/7 + 7/7

y = 5x/7 + 22/7

so your answer is B

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

step-by-step explanation: