f(t)= (t-5)^2 - 9 what are the zeros of the function? Smaller T: Larger t: What is the vertex of the parabola?: (__,__)

Smaller t = 2

Larger t = 5

Step-by-step explanation:

Given:

The given function is.

Find the zeros of the function.

Solution:

Simplify the equation above equation.

Now, we first find the root of the above equation.

Use quadratic formula with .

Put a, b and c value in above equation.

For positive sign

t = 2

For negative sign

t = 5

Put t = 2 in given function.

Put t = 5 in given function.

So, the zeros of the function is t = 2 or 5

Therefore, the smaller value of t = 2 and larger value of t = 5.

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west

4y - 6 + y^2 - 9 = y^2 + 4y - 15

y^2 term

terms

- terms

total of 3 terms when simplified

step-by-step explanation: