Mathematics, 18.08.2020 02:01, leo4687

2x + 3y = 7

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answered: StacySams7361

Step-by-step explanation:

Q: How do I solve 2X + 3Y = 7?

The two dimensional form for the equation of a straight line is: Y = mX + b (equation 0)

where X and Y are graphic coordinates of a point on that line.

m is the slope of the line described as (Y2-Y1)/(X2-X1) where (X1,Y1) and (X2,Y2) are the coordinates of two additional distinct points on that line.

b is the point on the Y axis where the line crosses called the Y Intercept.

Back to 2X + 3Y = 7

Subtract 2X from both sides of this equation:

2X + 3Y - 2X = 7 - 2X

3Y = -2X + 7

Divide both sides of the equation 3

3Y/3 = (-2X + 7)/3

Y = -(2/3)X + 7/3 (equation 1)

Examining this equation with respect to standard form shown (equation 0), this equation (equation 1) represents a line passing through the Y axis at point location 7/3 at a dowmward to the right slope of 2/3.

To find where the line crosses the X axis (X Intercept), set Y equal to 0:

0 = -(2/3)X + 7/3

Subtracting 7/3 from both sides of the equation:

-(7/3) = -(2/3)X + 7/3 - 7/3

-7/3 = -(2/3)X

Divide both sides of the equation by -2/3

(-7/3)/(-2/3)=((-2/3)X)/(-2/3)

To divide two fractions you invert the denominator and then multiply that by the numerator.

(-7/3)*(-3/2) = (-2/3)*(-3/2)*X

21/6 = (6/6)X

7/2 = X

So drawing a line between the coordinate pairs (0,7/3) also known as (X1,Y1) and (7/2,0) also known as (X2,Y2) describes a segment of the line satisfying the initial equation.

answered: Guest

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in $\delta bea$ and $\delta dea$ ;

$ba=da$ , as these are radii of our given circle.

$ea=ea$

therefore, $\delta bea\cong \delta dea$ by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

$3x-24=x+10$