A water wheel has a radius of 4 feet and the bottom of the wheel is 1 foot from the ground. One plank is painted white and it starts at the top of the wheel. The wheel is rolled forward through an angle of pi over 3 radians. How high from the ground is the white plank after this motion?

The height of the plank after the π/3 rotation motion is 8.464 ft

Step-by-step explanation:

The radius of the wheel = 4 ft

The elevation of the bottom of the wheel from the bottom = 1 foot

The angle to which the wheel is rolled = π/3 radians

The height of a rotating wheel is given by the following relation

f(t) = A·sin(B·t + C) + D

Where;

D = Mid line =  4 + 1 = 5 feet

B·t = π/3

C = 0

A = The amplitude = 4

Which gives;

f(t) = 4×sin(π/3) + 5 = 8.464 ft

The height of the plank after the π/3 rotation motion = 8.464 ft.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

hreryryrranswer:

step-by-step explanation: