The average score for all basketball players in a particular season has a mean of 75 and a standard deviation of 3.5. Suppose 49 played basketball today. Find the probability that the average score of the 49 players exceeded 76

0.0228

Step-by-step explanation:

Given that:

mean (μ) = 75, Standard deviation (σ) = 3.5

The z score is a score used in statistics to measure by how many standard deviations the raw score is above or below the mean. If the z score is positive, it means that the raw sore is above the mean and if the z score is negative then the raw score is below the mean. The z score is given by:

For x > 76 and a sample (n) = 49:

From the normal distribution table, the probability that the average score of the 49 players exceeded 76 = P(x > 76) = P(z > 2) = 1 - P(z < 2) = 1 - 0.9772 = 0.0228

8

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3