The results from the last test that ms. stone gave her class are 15,15,25,60 ,65,76,83,85,85,90.if she wants to persuade her class to study harder for the next quiz, what statistical measure should he use?

she should use the measurements of central tendency particularly the mean

Step-by-step explanation:

From the given data sets of test score

15,15,25,60 ,65,76,83,85,85,90

The mean score is

∑test score/no of scores = 599/10

= 59.9

This signifies that the average score is 59.9% slightly above average with this she can persuade them to study harder

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

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total $17.40