How many times does the graph of 4x = 32 - x2 cross the x-axis ? ОО
0 1
0 2

What are the solutions to the equation?

Step-by-step explanation:

● 4x = 32 - x^2

Add x^2 to both sides

● 4x +x^2 = 32 -x^2+x^2

● x^2 +4x = 32

Substract 32 from both sides

● x^2+4x -32 =32-32

● x^2 +4x-32=0

That is a quadratic equation

We will use the determinant method

The determinant is b^2-4ac

● a = 1

● b = 4

● c = 32

● b^2-4ac = 4^2 -4×1×(-32) = 144

144 is positive so the parabola will cross the x-axis two times

● x = (-b -/+ √(b^2-4ac))/2a

● x = (-4 +/- 12) /2

● x = 8/2 or x= -16/2

● x = 4 or x =-8

The solutions are 4 and -8

8y^50

step-by-step explanation:

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d