You have a box with 6 blue marbles, 7 red marbles, and 2 yellow marbles. You are going to pull out one marble, record its color, put it back in the box and draw another marble. What is the probability of
pulling out a yellow marble followed by a blue marble?

12/225 or 4/75.

Step-by-step explanation:

I hope this helps!

Answer as a fraction = 4/75

Answer in decimal form = 0.05333 (approximate)

Answer in percent form = 5.333% (approximate)

Work Shown:

A = event of pulling a yellow marble on the first selection

P(A) = 2/15 since there are 2 yellow out of 6+7+2=15 total.

B = event of pulling a blue marble on the second selection

P(B) = 6/15 = 2/5

Note how the 15 does not drop to 14 since we put the first marble back. Therefore events A and B are independent

P(A and B) = probability of getting yellow, then blue

P(A and B) = P(A)*P(B)

P(A and B) = (2/15)*(2/5)

P(A and B) = (2*2)/(15*5)

P(A and B) = 4/75

P(A and B) = 0.05333 approximately

P(A and B) = 5.333% approximately

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.

4th option is correct xy=-10

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