Write the equation of the line in slope intercept form that passes through (-2, -8) and (-9, 4) Please provide steps to solve if possible

Step-by-step explanation:

In order to find the slope-intercept form of a line when given two points, we need to first put it into point-slope form. The point-slope form is given by the equation:

Where m is the slope and x₁ and y₁ is one of the two points.

Anyways, let's first find the slope. Let's designate (-2,-8) as x₁ and y₁ and (-9,4) as x₂ and y₂ (it doesn't really matter). The formula for slope is:

So, the slope is -12/7.

Now, pick a point for the point-slope form. To keep things consistent, I'm going to use the point (-2,-8) as x₁ and y₁. Plug in -12/7 for m. Therefore:

Now, simplify, distribute, and isolate the y:

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5