Two kids at a summer camp, Tina and Winston, are competing in a potato sack race. Tina is younger, so she is given a head start of 33 meters. When the race starts, Tina hops at a rate of 1 meter per second, and Winston hops 4 meters per second. Eventually, Winston will overtake Tina. How long will that take? How far will Winston have to hop? It will take ___ seconds for Winston to hop ___ meters and catch up to Tina.

It will take Winston 11 seconds to hop 44 meters and catch up to Tina

Step-by-step explanation:

Set up an equation where x represents the number of seconds:

Tina will be represented by s + 33 since she goes 1 m/sec and she has a 33 meter head start, and Winston will be 4s. We need to find when Winston will catch up, so we need an equal sign.

s + 33 = 4s

Solve for s:

s + 33 = 4s

33 = 3s

11 = s

= 11 seconds

Then, plug in 11 as s to find how many meters he will go:

s + 33

11 + 33 = 44

= 44 meters

step-by-step explanation:

cats

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)