In an experiment you are to flip a two sided coin 100 times and record 55 heads up and 45 tails up. Determine the theoretical and experimental probability of getting a heads up in the experiment. theorical = 11/20, experimental = 11/20
theorical = 1/2, experimental = 1/2
theorical = 1/2, experimental = 11/20
theorical = 11/20, experimental = 1/2

theory=1/2, experimental=11/20

Step-by-step explanation:

so when talking about theoretical probability you only consider the only possible outcomes which are either head or tail and since you haven't carried out any sort of experiment yet (many flips) you consider the number of outcomes of tossed once since it's theory which are two therefore the probability of each will be 1/2

but in experimental probability you now consider the number of times tossed and the outcomes of each side which is this case of heads will be 55/100 but in the answers they have simplified so it will be 11/20

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.