3 married couples purchase 6 tickets that have them sitting together in a row at a basketball game. In how many ways can they be seated if they must be seated in couples

6

Step-by-step explanation:

We have 6 seats in a row:

1 2 3 4 5 6

We have 3 couples to fit into 3 slots:

Slot 1: First 2 seats

Slot 2: 2 middle seats

Slot 3: Last 2 seats

(Note: they can't sit in seats 2 and 3, with another couple in 4 and 5 - as the last couple would need to be separated in seats 1 and 6)

The first slot can have any of the 3 couples.

The second slot can have any of the 2 remaining couples.

The third slot can only have the 1 remaining couple.

3 options (slot 1), each of those having 2 options (slot 2), with each of those only having 1 option (slot 3).

Total number of options is thus,

3 * 2 * 1 = 6

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

41*67/2=1373.5

step-by-step explanation:

i just used a calculator