n the country of United States of Heightlandia, the height measurements of ten-year-old children are approximately normally distributed with a mean of 55.1 inches, and standard deviation of 5.8 inches. A) What is the probability that a randomly chosen child has a height of less than 46.3 inches

The probability is 0.0643 to 4 decimal places

Step-by-step explanation:

To calculate this probability, we find the z-score

Mathematically;

z-score = (x-mean)/SD

where in the question;

x = 46.3

mean = 55.1

SD = 5.8

Plugging these values, we have;

z-score = (46.3-55.1)/5.8 = -8.8/5.8 = -1.52

The probability we want to calculate is;

P(z < -1.52)

We can get this answer by using the standard normal distribution table;

Thus from the table, we have;

P(z < -1.52) = 0.064255 which is 0.0643 to 4 decimal places

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)