E Question Help 1.3.AP-9
Two hikers are 22 miles apart and walking toward each other. They meet in 4 hours. Find the rate of each hiker if one hiker walks 1.1 mph faster than the other
The speed of the slow hiker is mph, and the speed of the fast hiker is mph.

Step-by-step explanation:

Since, the hiker are walking at different speeds they meet at a point not in the middle.

Let distance travelled by Hiker A (slower) be x at speed s.

So, distance travelled by Hiker B (faster) is (22 - x) at a speed (s + 1.1) .

Solving equations 1 and 2, we get :

x = 8.8m and s = 2.2mph

Therefore,

Speed of Hiker A = 2.2 mph

Speed of Hiker A = 2.2 mphSpeed of Hiker B = 3.3 mph

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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