Given a20=100 and a50=400 identify the common difference “d”

a20=a+19d

or,100=a+19d

or, a=100-19d(I)

again,

a50=a+49d

or, 400=a+49d

or, a=400-49d(ii)

equating equations,we get

100-19d=400-49d

or, 30d=300

so, d=10

Step-by-step explanation:

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6x = 48

i hope this . 6 cards each and a total of $48. dvide each side by 6 and you will have your answer.

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation