(2t-3)^3, can you help me?, please?

8t^3-36t^2+54t-27

Step-by-step explanation:

(2t-3)^3

(2t-3)(2t-3)(2t-3)

Multiply the first two terms

(4t^2 -6t -6t+9)(2t-3)

Combine like terms

( 4t^2 -12t +9) ( 2t-3)

Multiply

2t*( 4t^2 -12t +9) -3 ( 4t^2 -12t +9)

Distribute

8t^3 -24t^2 +18t-12t^2 +36t-27

Combine like terms

8t^3-36t^2+54t-27

8t³ - 36t² + 54t - 27

Step-by-step explanation:

(2t - 3)³

(2t - 3)(2t - 3)(2t - 3)

FOIL the first two binomials - first - outer - inner - last

(2t - 3)(2t - 3)

= 4t² - 6t - 6t + 9

= 4t² - 12t + 9

multiply this polynomial by the last binomial

(4t² - 12t + 9)(2t - 3)

distribute 2t

2t • 4t² = 8t³

2t • -12t = -24t²

2t • 9 = 18t

distribute -3

-3 • 4t² = -12t²

-3 • -12t = 36t

-3 • 9 = -27

combine

8t³ - 24t² + 18t - 12t² + 36t - 27

simplify

8t³ - 36t² + 54t - 27

the answer will be

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.