Factor completely 2x2 + 9x + 4. (1 point) (2x + 2)(x + 4) (2x + 2)(x + 2) (2x + 4)(x + 1) (2x + 1)(x + 4)

(2x + 1)(x + 4)

Step-by-step explanation:

2x² + 9x + 4 cannot be factored normally - we must use the grouping technique (a > 1).

First, check for a GCF. Because there is not a GCF within this (factors of 9 are 1 and 3 - taking a 1 out is pointless), we will instead break the equation into two factors.

2x² will be apart of the first factor. You want to break the 9x into factors that will evenly break down with the 2x^2, so 3x will not work.

Your grouping factors should then be (2x^2 + 8x)(x + 4).

Then, take out the GCFs of the factors.

2x can come out of (2x^2 + 8x), so your new factor is 2x(x + 4). Your second factor set has no GCF, so you take out a 1 and get 1(x+4). In order to verify you did this correctly, the terms having the GCF distributed cannot be different in anyway.

Your factors are now (2x + 1)(x + 4) take the two GCFs and make them a factor set, then the second factor is the common factor.

step-by-step explanation:

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