The expression 100 + 20m100+20m100, plus, 20, m gives the volume of water in Eduardo's pool (in liters) after Eduardo spends mmm minutes filling his pool. What is the volume of water in Eduardo's pool after he fills it for 5 \dfrac145 4 1 5, start fraction, 1, divided by, 4, end fraction minutes?

205 litres

Step-by-step explanation:

Given:

Volume of water is given as:

(in litres)

m is the time in minutes spent filling water in Eduardo's pool.

To find:

Volume of water in the pool after the water is filled for minutes.

Solution:

Here, volume of water in the Pool (in litres) is given by the equation:

....... (1)

Where m is the time for which Eduardo fills the pool.

Here, we are also given that

m = minutes = minutes

And we have to find the value of V after minutes.

Let us put the value of m as minutes in the equation (1) to find the value of V.

So, the volume of water in the pool after minutes is 205 litres.

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation:

to find the perimeter, you add up all the lengths of the sides. in this case you would have to add up 18+22+40+80 which equals 160.