please do the steps solve the equation for d: 1/6d-8=5/8 2. Solve the equation for x: 3x-4+5x=10-2z 3. Solve the equation for c: 7(c-3)=14 4. Solve the equation for m: 11(m/22+3/44)=87m+m 5. Solve the equation for k: ck+5k=a

Step-by-step explanation:

1. 1/6d - 8 = 5/8

1/6d -8 + 8 = 5/8 + 8

1/6d = 69/8

1/6d / 1/6 = 69/8 / 1/6

d = 51.75 or

2. 3x - 4 + 5x = 10 - 2z

8x - 4 = 10 - 2z

8x - 4 + 4 = 10 - 2z + 4

8x = 14 - 2z

8x / 8 = (14 - 2z) / 8

x =

3. 7(c  - 3) = 14

7(c - 3) / 7 = 14 / 7

c - 3 = 2

c - 3 + 3 = 2 + 3

c = 5

4. 11(m / 22 + 3 / 44) = 87

m / 22 + 3 / 44 = 87 / 11

m / 22 + 3 / 44 = 348 / 44

m / 22 = 345 / 44

m = 172.5

5. ck + 5k = a

k(c + 5) = a

k =

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine