Mathematics, 14.08.2020 14:01, tiakimberly3

One spring day, Dylan noted the time of day and the temperature, in degrees Fahrenheit. His findings are as follows: At 6 a. m., the temperature was 56° F. For the
next 2 hours, the temperature rose 3° per hour. For the next 3 hours, it rose 4º per
hour. The temperature then stayed steady until 6 p. m. For the next 4 hours, the
temperature dropped 3° per hour. The temperature then dropped steadily until the
temperature was 61° at midnight. On the set of axes below, graph Dylan's data.
Hel pleas I’m terrible with graphing

Answers: 1

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Answers

Since Dylan noted the time of day and the temperature, in degrees Fahrenheit, and his findings are as follows: At 6 am, the temperature was 56 ° F, for the next 2 hours, the temperature rose 3 ° per hour, for the next 3 hours, it rose 4º per hour, and the temperature then stayed steady until 6 pm, while for the next 4 hours, the temperature dropped 3 ° per hour, and the temperature then dropped steadily until the temperature was 61 ° at midnight , to determine the average temperatures, the following tables must be made:

6 AM = 56

7 AM = 59

8 AM = 62

9 AM = 66

10 AM = 70

11 AM = 74

6 PM = 74

7 PM = 71

8 PM = 68

9 PM = 65

10 PM = 62

11 PM = 61.5

12 AM = 61

Thus, the average daily temperature was 68°F.

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One spring day, Dylan noted the time of day and the temperature, in degrees

Fahrenheit. His finding

answered: Peachyyyyyy978

Please find attached the required graph for the temperature time relationship

Step-by-step explanation:

The parameters given are arranged in a tabular form as follows;

Time Temperature

6 a. m. 56° F

7 a. m. 59° F

8 a. m. 62° F

9 a. m. 66° F

10 a. m. 70° F

11 a. m. 74° F

12 p. m. 74°F

1 p. m. 74°F

2 p. m. 74°F

3 p. m. 74°F

4 p. m. 74°F

5 p. m. 74°F

6 p. m. 74°F

7 p. m. 71°F

8 p. m. 68°F

9 p. m. 65°F

10 p. m. 62°F

11 p. m. 61.5°F

12 a. m. 61°F

With the above table as the data points, the graph can be drawn

From Excel, The Mean temperature is approximately 68.1°F

The standard deviation is 6.079 °F

answered: Guest

$w\geq 14$

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

$2l+2w\geq 40$

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

$2\times 6+2w\geq 40$

now, we can solve for w

$12+2w\geq 40$

subtract both sides by 12

$12+2w-12\geq 40-12$

$2w\geq 28$

divide both sides by 2

and we get

$w\geq 14$

so,

the smallest possible measurement of the width is 14 feet

answered: Guest

step-by-step explanation:

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One spring day, Dylan noted the time of day and the temperature, in degrees Fahrenheit. His finding...