Given that a random variable X is normally distributed with a mean of 2 and a variance of 4, find the value of x such that P(X < x)

Given that a random variable X is normally distributed with a mean of 2 and a variance of 4, find the value of x such that P(X < x)=0.99   using the cumulative standard normal distribution table

6.642

Step-by-step explanation:

Given that mean = 2

standard deviation = 2

Let X be the random Variable

Then X N(n,)

X N(2,2)

By Central limit theorem;

P(X<x) = 0.09

P(X < x) = 0.99

X -2 = 2.321 × 2

X -2 = 4.642

X = 4.642 +2

X = 6.642

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

pls mark as brainliest

sine

step-by-step explanation: