5. During a national debate on changes to health care, a cable news service performs an opinion poll of 500 small business owners. It shows that 65% of small-business owners do not approve of health care changes. Develop a 95% confidence interval for the proportion opposing health care changes. Use 4 decimal places.

The 95% confidence interval for the proportion opposing health care changes is (0.6082, 0.6918).

Step-by-step explanation:

The (1 - α)% confidence interval for the population proportion is:

The information provided is:

The critical value of z for 95% confidence level is:

*Use a z-table.

Compute the 95% confidence interval for the proportion opposing health care changes as follows:

Thus, the 95% confidence interval for the proportion opposing health care changes is (0.6082, 0.6918).