Ken said that he is going to reduce the number of calories that he eats during the day. Ken's trainer asked him to start off small and reduce the number of calories by no more than 7%.

Ok, this question seems incomplete, so i will answer it in a general way.

Suppose that regularly, Ken eats A calories during the day. (A is a positive number)

Now, Ken wants to reduce this number, but his nutritionist tells him to reduce no more than 7% (So the max reduction possible is a reduction of the 7%).

So after the reduction, Ken eats C calories per day.

First, the maximum reduction that Ken can do is when he reduces exactly 7% of the calories.

So if he regularly consumes A calories, the reduction will be of

(7%/100%)*A = 0.07*A

So after the reduction, the amount of calories that he consumes per day is:

C = A - 0.07*A = A*(1 - 0.07) = A*0.93

But this is the minimum amount of calories that he can consume, the actual range of possible options will be:

A < C ≤ A*0.97.

C is strictly smaller than A because we must have a reduction in the number of calories.

Those values of C is all the posible amounts of calories that Ken eats per day after the initial reduction in the number of calories per day.

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10