Both Fred and Ed have a bag of candy containing a lemon drop, a cherry drop, and a lollipop. Each takes out a piece and eats it. What are the possible pairs of candies eaten? A. Lemon-lemon, cherry-lemon, lollipop-lollipop, lemon-cherry, cherry-cherry, lemon-lollipop, lollipop-cherry, cherry-lollipop, lollipop-lemon B. Cherry-lemon, lemon-lollipop, lollipop-cherry, lollipop-lollipop, lemon-lemon C. Lemon-cherry, lemon-cherry, lemon-cherry, lemon-lollipop, lemon-lollipop, lemon-lollipop, cherry-lollipop, cherry-lollipop, cherry-lollipop D. Lemon-lemon, cherry-lemon, lollipop-lollipop, lemon-lollipop, cherry-cherry, lemon-lollipop, lollipop-cherry, cherry-lemon, lollipop-lemon

A. Lemon-lemon, cherry-lemon, lollipop-lollipop, lemon-cherry, cherry-cherry, lemon-lollipop, lollipop-cherry, cherry-lollipop, lollipop-lemon

Step-by-step explanation:

From the above question, we are told that both Fred and Ed have a bag of candy containing a lemon drop, a cherry drop, and a lollipop

There are two events here's

2 people = Fred and Ed

3 bags of different sweets = Lemon Cherry and Lollipop

The number of ways that both of them can eat this singly is calculated using combination formula

C(n, r) = nCr = n!/r! (n - r)!

n = 3, r = 2 = 3C2 = 3!/2! (3 - 2)!

= 3 × 2 × 1/2 × 1

= 3

We were asked to find the possible pairs

Hence = 3² = 9

There are 9 possible pairs through which Fred and Ed can eat their sweets and they are:

1) Lemon - Lemon

2) Cherry - Cherry

3) Lollipop - Lollipop

4) Lemon - Cherry

5) Cherry - Lemon

6) Lollipop - Cherry

7) Cherry - Lollipop

8) Lollipop - Lemon

9) Lemon - Lollipop.

Therefore, Option A is the correct option

answer: idk

step-by-step explanation: