The distance between two schools A and B is 2km. A market is situated 3/4 of the distance from A to B. How far is the market from B?

0.5 km

Step-by-step explanation:

the schools are 2km apart, so we are trying to find 3/4 of 2km, which is 1.5. So, the market is 1.5km from school A, which means that it is .5km from school b since they are 2km apart

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

false

step-by-step explanation: