20 liters of mixture contain milk nad water in the ratio 5:3 of 4 liters of the mixture are replaced by 4 liters of milk find the new ratio of milk to water

7:3

Step-by-step explanation:

5 + 3 = 8

The ratio is

5 milk : 3 water : 8 total

Milk is 5/8 of the total.

Water is 3/8 of the total.

The 20-liter mixture contains:

5/8 * 20 = 12.5 liters of milk, and

3/8 * 20 = 7.5 liters of water

4 liters of the mixture contain:

5/8 * 4 = 2.5 liters of milk, and

3/8 * 4 = 1.5 liter of water

When you remove 4 liters of the mixture from 20 liters of the mixture, you end up with

12.5 L - 2.5 L = 10 L milk, and

7.5 L - 1.5 L = 6 L water

Now you add 4 liters of milk. Now you have

10 L + 4 L = 14 L milk

6 L water

The new ratio of milk to water is 14:6 = 7:3

Answer

Step-by-step explanation:

sum of ratio=5+3=8

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

d

step-by-step explanation: