Hungry Harry is a giant ogre with an even bigger appetite. After Harry wakes up from hibernation, his daily hunger H(t)H(t)H, left parenthesis, t, right parenthesis (in \text{kg}kgstart text, k, g, end text of pigs) as a function of time ttt (in hours) can be modeled by a sinusoidal expression of the form a\cdot\cos(b\cdot t)+da⋅cos(b⋅t)+da, dot, cosine, left parenthesis, b, dot, t, right parenthesis, plus, d. When Harry wakes up at t=0t=0t, equals, 0, his hunger is at a maximum, and he desires 30 \text{ kg}30 kg30, start text, space, k, g, end text of pigs. Within 222 hours, his hunger subsides to its minimum, when he only desires 15 \text{ kg}15 kg15, start text, space, k, g, end text of pigs. Find H(t)H(t)H, left parenthesis, t, right parenthesis. \textit{t}tstart text, t, end text should be in radians.

Complete Question

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Harry's  hunger is  

Step-by-step explanation:

From the question we are told

 The  hunger of harry is      

 The hunger of harry is  maximum at  t =  0  

 The hunger of harry is minimum at  t =  2 hours

 The mass of pig desires at maximum hunger is

 The mass of  pig desires at minimum hunger is  

Generally at maximum hunger we have

=>      

=>      

Now  at minimum hunger

Generally the  minimum value of  

So

  At minimum

=>                    

Generally from trigonometric rules

                   here  n =  0 , 1 , 2 , 3  

Now since we are considering the minimum  =  0  

   So  

=>        

So

=>              

So

=>    

Adding  

      =>    

From equation 1

=>    

So we can represent the harry hunger as  

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)