Find the values of x which satisfy the following inequation:
x3 – x² <12x

x< -3 and 0 < x < 4

Step-by-step explanation:

x^3 – x² <12x

Subtract 12x from each side

x^3 -x^2 - 12x< 0

Factor

x( x^2 -x-12) <0

Factor

x( x-4) ( x+3) < 0

Using the zero product property

x=0   x=4  x=-3

We have to check the signs regions

x < -3

-( -) (-) < 0   True

-3 to 0

-( -) (+) < 0   False

0 to 4

+( -) (+) < 0   True

x>4

+( +) (+) < 0   False

The regions this is valid is

x< -3 and 0 < x < 4

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

i got 10.28 but that rounds up to 10.3