If the sin of angle x is four fifths and the triangle was dilated to be two times as big as the original, what would be the value of the sin of x for the dilated triangle? Clue: Use the slash symbol ( / ) to represent the fraction bar, and enter the fraction with no spaces.

Hey there! I'm happy to help!

Sine is a trigonometric ratio. It is the ratio of the opposite side of the angle to the hypotenuse. Since it is a ratio, it does matter how big or small the triangle is as long as the sides remain in proportion. If the opposite side is 4 and the hypotenuse is 5, the sine of x will be the same as it would be if the opposite were 16 and the hypotenuse were 20 because they simplify to the same ratio (4/5).

The sine (or any trigonometric ratio) of any number stays the same even if the triangle is dilated because the proportion between the sides stays the same no matter how big or small. So, they told us the answer at the beginning. The sine of angle x is 4/5.

Have a wonderful day! :D

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

i dont know men

step-by-step explanation: