Can someone please help me I need the answer urgently please

Step-by-step explanation:

AB ≅ BC.  So, ΔABC is an isosceles triangle

Opposite angles of equal sides are equal.

∠BAC = ∠BCA = x°

In ΔABC,

∠ABC + ∠BAC + ∠BCA = 180  {Angle sum property of triangle}

 56 + x + x = 180

56 + 2x = 180

        2x = 180 - 56

         2x = 124

           x = 124/2

           x = 62°

∠BAC = ∠BCA =  62°

∠DCF = ∠BCA   {Vertically opposite angles}

∠DCF = 62°

CDEF is a parallelogram.

In parallelogram, opposite angles are congruent.

∠DEF = ∠DCF

∠DEF = 62°

In a parallelogram, sum of adjacent angles = 180

∠DEF + ∠CDE = 180

62 + ∠CDE = 180

       ∠CDE = 180 - 62

      ∠CDE = 118°

∠CFE = ∠CDE   {In parallelogram, opposite angles are congruent}

∠CFE  = 118°

10

step-by-step explanation:

7+3=10

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b