Find the area of each polygon

1. 66 ft²

2. 102 cm²

3. 35 in.²

4. 7.36 in.²

5. 60 in.²

6. 91 m²

7. 48 m²

5. 567 mm²

9. 255 m²

10. The side length of the square is 9 cm

The area of the square is 81 cm²

Step-by-step explanation:

1. The area of the parallelogram = 11 × 6 = 66 ft²

2. The area of the triangle = 1/2×12×17 = 102 cm²

3. The area of the trapezium = 1/2×(5 + 9)×5 = 35 in.²

4. The area of the triangle = 1/2×4.6×3.2 = 7.36 in.²

5. The area of the parallelogram = 10 × 6 = 60 in.²

6. The area of the trapezium = 1/2×(15 + 11)×7 = 91 m²

7. The area of the parallelogram = 8 × 6 = 48 m²

5. The area of the trapezium = 1/2×(27 + 36)×18 = 567 mm²

9. The height of the wall = 17 m - 8 m = 15 m

The area = 17 × 15 = 255 m²

10. The dimensions of a square with perimeter = 36 cm are;

Side length = 36/4 = 9 cm

The area of the square = 9 × 9 = 81 cm².

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy