A circular hall has a hemispherical roof. The greatest height is equal to the
inner diameter. If the capacity of
the hals is
the
floor is.
43510 m^3

then
area
of the

Area=1,288.88m²

Step-by-step explanation:

A circular hall(big room) has a hemispherical roof.The greatest height is equal to the inner diameter.Find the area of the floor,given that the capacity of the hall is 43510 cubic meter

Solution

let

diameter = D

radius,r = D/2

Greatest height = D

height of cylindrical part (h)= D-r = r

radius of cylindrical part = r

area of floor = πr²

volume = volume of cylindrical part + volume of hemispherical part

= πr²h + 2/3 πr³

Recall h=r

volume = πr³ + 2/3 πr³

43510=5/3πr³

Make r the subject

r=3√(43510*3)/5π

=3√(130,530/15.7

=3√8,314.01

=20.26

Area of floor = πr²

=3.14*(20.26)²

=3.14*410.47

=1,288.88m²

5 pm

step-by-step explanation:

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.