The diagram below models the layout at a carnival where G, R, P, C, B, and E are various locations on the grounds. GRPC is a parallelogram. Parallelogram GRPC with point B between C and P forming triangle GCB where GC equals 375 ft, CB equals 325 ft, and GB equals 425 ft, point E is outside parallelogram and segments BE and PE form triangle BPE where BP equals 225 ft. !Part A: Identify a pair of similar triangles. (2 points) !Part B: Explain how you know the triangles from Part A are similar. (4 points) !Part C: Find the distance from B to E and from P to E. Show your work. (4 points)

Step-by-step explanation:

Part A: ΔGCB ~ ΔEPB

Part B: ∠GBC and ∠EBP are vertical angles, and therefore congruent.

∠GCB and ∠EPB are alternate interior angles, and therefore congruent.

So ΔGCB and ΔEPB are similar by AA similarity.

Part C:

BE / BP = BG / BC

BE / 225 = 425 / 325

BE ≈ 294

PE / BP = CG / BC

PE / 225 = 375 / 325

PE ≈ 260

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )