A city council consists of seven Democrats and six Republicans. If a committee of five people is selected, find the probability of selecting two Democrats and three Republicans.

solution,

let d and r denote democrats and republicans respectively.

given,

no. of total sample space n(s) =7+6=13

no. of total democrats n(d)=7

no. of total republicans n(r)=6

no. of democrats events n(D1)=2

no. of republicans events n(R1)=3

it is a mutually exclusive event. so the probability of selecting two democrats and three republicans= {n(D1)/n(s)} * {n(r1)/n(s)}

=(2/13)*(3/13)

=6/169

answer: idk wbu

step-by-step explanation: