On a coordinate plane, line P Q goes through (negative 6, 4) and (4, negative 4). Point R On a coordinate plane, a line goes through (negative 4, 0) and (4, negative 4). A point is at (2, 3). What is the equation of the line that is parallel to the given line and passes through the point (2, 3)? x + 2y = 4 x + 2y = 8 2x + y = 4 2x + y = 8

x + 2y = 8.

Step-by-step explanation:

Line goes through (-4, 0) and (4, -4).

The slope is (-4 - 0) / (4 - -4) = -4 / (4 + 4) = -4 / 8 = -1/2.

Since we are looking for the equation of the line parallel to that line, the slope will be the same.

We have an equation of y = -1/2x + b. We have a point at (2, 3). We can then say that y = 3 when x = 2.

3 = (-1/2) * 2 + b

b - 1 = 3

b = 4.

So, we have y = -1/2x + 4.

1/2x + y = 4

x + 2y = 8.

Hope this helps!

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step-by-step explanation: