Mathematics
Mathematics, 12.08.2020 04:01, 06takmay48639

-\dfrac{1}{6} \times \left(-\dfrac{9}{7}\right)βˆ’ 6 1 Γ—(βˆ’ 7 9 )minus, start fraction, 1, divided by, 6, end fraction, times, left parenthesis, minus, start fraction, 9, divided by, 7, end fraction, right parenthesis

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-\dfrac{1}{6} \times \left(-\dfrac{9}{7}\right)βˆ’ 6 1 Γ—(βˆ’ 7 9 )minus, start fraction, 1, divided by...

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