Please answer. I need this to be done, Thanks. Will give brainliest

p^ -1 q ^ -59  s ^26

or without negative exponents

s^ 26 /(p q^ 59)

Step-by-step explanation:

When multiplying , we can add the exponents when the bases are the same

p^0 q ^ -60 r^-1 s^25  * p^-1 qrs

When there is no exponent written, there is an implied 1

p^ (0+-1) q^(-60+1) r ^( -1 +1) s ^ ( 25+1)

p^ -1 q ^ -59 r ^0 s ^26

r^0 = 1

p^ -1 q ^ -59  s ^26

If you need  the negative exponents written as positive

a^-b = 1/ a^b

s^ 26 /(p q^ 59)

its 4 because 2 times 2 is 4, if you double the number two you get four

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1