. Find the sum of the geometric sequence. (1 point) 1, one divided by four, one divided by sixteen, one divided by sixty four, one divided by two hundred and fifty six

0.332

Step-by-step explanation:

given series

1/4, 1/16,1/64.1/256

this is geometric series

where common ratio   r is given by

nth term/ (n-1)th term

let the second term is nth term and first term is (n-1)th term

r = 1/16 / (1/4) = 1/4

sum of series is given by

a (1-r^n)/1-r

where a is first term

n is the number of terms

r is the common ration

in the given series

1/4, 1/16,1/64.1/256

a = 1/4

r = 1/4

n = 4

thus ,

sum = 1/4(1-(1/4)^4)/ (1-1/4)

sum = 1/4(1-(1/256)/(4-1)/4

sum = 1/4((256-1)/256 / 3/4

1/4 in numerator and denominator gets cancelled

sum =( 255/256*3) = 255/768 = 0.332

Thus, sum of series is 0.332.

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.