Three people are standing on a Cartesian coordinate plane. Robert is standing at point $(4,3)$, Lucy at point $(6,1)$, and Liz at point $(1,7)$. How many units away is the farther person from Robert?

Liz, she is 5 units away from Robbert.

Step-by-step explanation:

Ok, the data that we have is:

Robert is at (4,3 )

Lucy is at (6, 1)

Liz is at (1, 7)

We want to find the units between Robert and the person that is farther away from him.

The distance between Robert and Lucy can be calculated as:

First we calculate the difference in the point or in the position vector:

(4, 3) - (6, 1) = (4 - 6, 3 - 1) = (-2, 2)

To calculate the exact distance, we need to calculate the magnitude of this point, this is:

For a point (x, y), the magnitude is M = √(x^2 + y^2)

Then we have:

D = √( (-2)^2 + 2^2) = √8

Now, the distance between Robert and Liz can be calculated in the same way:

(4, 3) - (1, 7) = (4 - 1, 3 - 7) = (3, -4)

The magnitude is:

D = √(3^2 + (-4)^2) = √(9 + 16) = √25 = 5

Now, we know that 5 > √8

Then the person that is farthest away from Robert is Liz, and she is 5 units away.