When a fish is selected at random from a tank, the probability that it has a green tail is 0.36, the probability that it has red fins is 0.59, and the probability that it has both a green tail and red fins is 0.21. What is the probability that the selected fish will not have a red fin or a green tail?

0.26

Step-by-step explanation:

As per given , we have

P(green tail) = 0.36

P(red fins) = 0.59

P(both a green tail and red fins ) = 0.21

Now, P(Neither red fin nor green tail )= 1 - P(either red fin or green tail )

[P(neither A nor B)= 1- P(either A or B)]

= 1-(P(green tail) +P(red fins)+P(both a green tail and red fins ))

[P(A or B)= P(A)+P(B)-P(A and B)]

= 1- (0.36+0.59-0.21)

= 1-(0.74)

= 0.26

Hence, the probability that the selected fish will not have a red fin or a green tail = 0.26

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3

it's d

step-by-step explanation: