Mathematics
Mathematics, 12.08.2020 07:01, kingalbyss1230

Suppose two events A and B are independent, with P(A) โ‰  0 and P(B) โ‰  0. By working through the following steps, you'll see why two independent events are not mutually exclusive. (a) What formula is used to compute P(A and B)? P(A) + P(B) P(A) / P(B) P(A) โˆ’ P(B) P(A) ยท P(B) Is P(A and B) โ‰  0? Explain. Yes. Even if P(A) = 0 or P(B) = 0, P(A and B) will always be non-zero. No. Because both P(A) and P(B) are not equal to 0, P(A and B) = 0. No. P(A and B) = 0. Yes. Because both P(A) and P(B) are not equal to 0, P(A and B) โ‰  0. (b) Using the information from part (a), can you conclude that events A and B are not mutually exclusive? No. Two events being independent always implies they are mutually exclusive. No. Because P(A and B) โ‰  0, A and B are mutually exclusive. Yes. Two events being independent always implies they are mutually exclusive. Yes. Because P(A and B) โ‰  0, A and B are not mutually exclusive.

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Suppose two events A and B are independent, with P(A) โ‰  0 and P(B) โ‰  0. By working through the follo...

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