A survey of athletes at a high school is conducted, and the following facts are discovered: 28% of the athletes are football players, 25% are basketball players, and 24% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that they are either a football player or a basketball player

0.29 or 29%

Step-by-step explanation:

Given :

Probability that the athletes are football players : P(football ) = 0.28

Probability that the athletes are basketball players : P(basketball) = 0.25

Probability that the athletes play both football and basketball: P( both football and basketball ) = 0.24

Now, using formula

P(either  football or basketball)= P(football )+ P(basketball+ P( both football and basketball )

⇒P(either  football or basketball)= 0.28+0.25-0.24 = 0.29

Hence, the probability that they are either a football player or a basketball player = 0.29 .

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!