Mathematics, 05.08.2020 05:01, dxpebetty64
Locate the points of discontinuity in the piecewise function shown below.
|-(x + 1)2 + 2; - < x < -1
f(x) = {-4 + 2; -1 < x <2
VE - 1;
2
O A.
x= -1 and 2
OB.
x = 2
Oc.
x= -1
OD.
no points of discontinuity
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Locate the points of discontinuity in the piecewise function shown below.
|-(x + 1)2 + 2; - < x...
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