The admission fee at a carnival fair is $4.50 for children and $8.00 for adults. One day, 2200 people attended the fair
and $5050 was collected. How many children and how many
adults attended?
Lets say:
c= number of children
a= number of adults

Adult=1,385.71

Children=814.29

Approximately

Adult=1386

Children=814

Step-by-step explanation:

c= number of children

a= number of adults

Admission fee for children=$4.50

Admission fee for adults=$8.00

Total attendees=2200

Total amount realized=$5050

We need two equations to solve the two unknowns

c + a=2200 (1)

4.50c + 8.00a=5,050 (2)

From (1)

c + a=2200

c=2200 - a

Substitute c=2200 - a into (2)

4.50c + 8.00a=5,050

4.50(2200 - a) + 8.00a=5050

9900 - 4.50a +8.00a=5050

Collect like terms

9900-5050= -4.50a+8.00a

4,850=3.5a

Divide both sides by 3.5

1,385.71=a

Substitute a=1,385,71 into (1)

c + a=2200

c+1385.71=2200

c=2200-1385.71

=814.29

c=814.29

21

step-by-step explanation:

11279

step-by-step explanation:

for exempl this   system of equations   y = x - 3

                                                                y = 2x - 5

look   the line : y = x -3     ( red)

                            the line : y = 2x -5 ( bleus)